3h^2+53=-19-30h

Solution for 3h^2+53=-19-30h equation:

3h^2+53=-19-30h

We move all terms to the left:

3h^2+53-(-19-30h)=0

We add all the numbers together, and all the variables

3h^2-(-30h-19)+53=0

We get rid of parentheses

3h^2+30h+19+53=0

We add all the numbers together, and all the variables

3h^2+30h+72=0

a = 3; b = 30; c = +72;
Δ = b2-4ac
Δ = 302-4·3·72
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6}{2*3}=\frac{-36}{6}
=-6
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6}{2*3}=\frac{-24}{6}
=-4
$